In r-programming: i want to use the same method to handle cases 1 and 10, ie, when the loop is in round 1 and then in 10 again. same for 2 and 11. is there a way to have several case expressions being handled by the same method for k == 1 and later also fo 10 it should use the first case and for k ==2 and later 11 it should use the second case. the above code doesn't work.

```
for(i in 1:x) {
switch(k,
"1", "10"= {
correct <- test[21,1]
current <- test[i-p,1]
if(all(correct == current)){
answers[i-p,k] <- c(1)
} else{
answers[i-p,k] <- c(0)
}
},
"2","11" ={
correct <- test[21,2]
current <- test[i,2]
if(all(correct == current)){
answers[i,k] <- c(1)
} else{
answers[i,k] <- c(0)
}
}
}
```

the same code for only one case expression works:

```
for(i in 1:x) {
switch(k,
"1" = {
correct <- test[21,1]
current <- test[i-p,1]
if(all(correct == current)){
answers[i-p,k] <- c(1)
} else{
answers[i-p,k] <- c(0)
}
},
"2" ={
correct <- test[21,2]
current <- test[i,2]
if(all(correct == current)){
answers[i,k] <- c(1)
} else{
answers[i,k] <- c(0)
}
}
}
```

in java we can use case 1 : case 2 to do that. how is it done in r? i appreciate your help. alternatively i could also copy the code but don't want to if i can avoid it.

Answer:

My personal choice would be to remap your `k`

to the overlapping cases. Example:

```
k<-1:20
kmatch<-(k-1)%%9 +1
# [1] 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 1 2
```

Then feed `kmatch`

to your `case`

expression

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