I have the following dataframe:

`data <- data.frame(week = c(rep("2014-01-06", 3), rep("2014-01-13", 3), rep("2014-01-20", 3)), values = c(1, 2, 3))`

```
week values
1 2014-01-06 1
2 2014-01-06 2
3 2014-01-06 3
4 2014-01-13 1
5 2014-01-13 2
6 2014-01-13 3
7 2014-01-20 1
8 2014-01-20 2
9 2014-01-20 3
```

I'm wanting to create a column in `data`

that counts the unique `week`

and assigns it a sequential value, such that the df appears like this:

```
week values seq_value
1 2014-01-06 1 1
2 2014-01-06 2 1
3 2014-01-06 3 1
4 2014-01-13 1 2
5 2014-01-13 2 2
6 2014-01-13 3 2
7 2014-01-20 1 3
8 2014-01-20 2 3
9 2014-01-20 3 3
```

Answer:

You could use `base R`

by converting the "week" column to `factor`

and specifying the levels as the `unique`

values of "week". Convert `factor`

to `numeric`

and get the numeric index of the levels.

```
data$seq_value <- with(data, as.numeric(factor(week,levels=unique(week) )))
data$seq_value
#[1] 1 1 1 2 2 2 3 3 3
```

Or `match`

the "week" column to `unique`

values of that column to get the `numeric`

index.

```
with(data, match(week, unique(week)))
#[1] 1 1 1 2 2 2 3 3 3
```

Or using `data.table`

, by first converting `data.frame`

to `data.table`

(`setDT`

) and then get the index values (`.GRP`

) of grouping variable 'week' and assign it to new column `seq_value`

```
library(data.table)
setDT(data)[,seq_value:=.GRP, week][]
```

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