regex,bash,format,timestamp,date-formatting , Bash - Pattern matching an argument against the timestamp format
Bash - Pattern matching an argument against the timestamp format
Question:
Tag: regex,bash,format,timestamp,date-formatting
I have a script that is supposed to take in as input a timestamp of the format:
YYYY-mm-dd HH:mi:ss
I use the following to check if the input conforms to the pattern:
if [[ "$1" == "-r" && "$2" == '[0-9]{4}-[0-9]{2}-[0-9]{2} [0-9]{2}:[0-9]{2}:[0-9]{2}' ]]
If it does not match the pattern, it is supposed to throw an error. I turned on bash logging, and passed the following as input:
./meta_script_test.sh -r '2014-01-01 00:00:00'
The log that is generated by the bash -x declaration shows this:
[[ 2014-01-01 00:00:00 == \[\0\-\9\]\{\4\}\-\[\0\-\9\]\{\2\}\-\[\0\-\9\]\{\2\}\ \[\0\-\9\]\{\2\}\:\[\0\-\9\]\{\2\}\:\[\0\-\9\]\{\2\} ]]
+ usage 'Timestamp is in an improper format. Please enter it as: YYYY-mm-dd 00:00:00, and try again'
+ cat
Usage: ./meta_script_test.sh -r 'timestamp'
-r for reset is used to manually pass a date in timestamp format in case of data corruption for creating the delta table.
Example: ./meta_script_test.sh -r '2014-01-01 00:00:00'
I have tried various combinations of the if statement like:
if [[ "$1" == "-r" && "$2" == '\[0-9]{4}-\[0-9]{2}-\[0-9]{2} \[0-9]{2}:\[0-9]{2}:\[0-9]{2}' ]]
And
if [[ "$1" == "-r" && "$2" == '\(d){4}-\(d){2}-\(d){2} \(d){2}:\(d){2}:\(d){2}' ]]
Nothing seems to be working. Can you please point me to the right regex for matching the parameter correctly to the timestamp format? Thanks!
Answer:
Use =~ to perform a regular expression match. == is for exact matches or matching a file globbing pattern. The regexp shouldn't be quoted; since your regexp contains a space, you need to escape or quote that character.
if [[ "$1" == "-r" && "$2" =~ [0-9]{4}-[0-9]{2}-[0-9]{2}\ [0-9]{2}:[0-9]{2}:[0-9]{2} ]]
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