java,spring,spring-integration , spring : adding params for router
spring : adding params for router
Question:
Tag: java,spring,spring-integration
I'm using spring router to decide which of 2 channels to go through. I wan't to pass to the service that gives back an answer one of the values in the payload and not the payload itself. How can I do that? I didn't really find a use case like this, I thought maybe it could be done by using enricher. Any suggestions?
My code :
<int:router id="aggregationRouter"
input-channel="aggregationPathRouterInputChannel"
ref="decideAggregationByName"
>
<int:mapping value="true" channel="SumAggregatorChannel" />
<int:mapping value="false" channel="AvgAggregatorChannel"/>
</int:router>
the decideAggregationByName gets an input which is a string (name) and returns a boolean. I don't know how to pass the string argument that is a member inside the payload I get in this step
Answer:
Most Spring Integration components provide an expression
option in contradiction to the ref
and method
. So, if your payload
is a Map
(for example), but your decideAggregationByName
requires String
as an argument and you know which key
represents a value
for that arg you can do that like this:
<int:router id="aggregationRouter"
input-channel="aggregationPathRouterInputChannel"
expression="@decideAggregationByName.doDecision(payload['key'])"
>
From other side you can rework that target method to accept whole payload
object and extract desired String
from the code manually.
Otherwise I'm not sure what is the issue is in front of you.
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