c,random,command,argv,argc , How do I make a function print out a certain amount of Random numbers through the command line? C


How do I make a function print out a certain amount of Random numbers through the command line? C

Question:

Tag: c,random,command,argv,argc

How do I pass an arguement and print that amount of numbers in my program? So far I have found out that if I change count to a lower number than argc, the amount of numbers increases. However, I want it to print x amount of numbers on whatever I type in the command line like 10. Thanks

int random( int limi, int lims);

int main (int argc, char *argv[])
{
 int count;
srand(time(NULL));
int p;
int input;
int i = 0;


if (argc > 1)
{
  for ( count = 1; count < argc; count++)
{

 p = random(-10000,10000);

  printf(" %d\n",p );


}
}
else
  {
    printf("The command had no other arguments.\n");
  }

return 0;
}

int random( int limi, int lims )
{
          return ( rand() % (lims - limi) - lims);
 }

Answer:

The arguments to your application are passed in as an array of strings in argv[]. To convert the first argument to an integer, parse it using atoi(), strtol() or sscanf():

if (argc > 1)
{
    int amount = atoi(argv[1]);
    for ( count = 1; count < amount; count++)
    {
         p = random(-10000,10000);

         printf(" %d\n",p );

    }
}

The arguments start from argv[1]. argv[0] will be the name of your program.


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