neo4j,cypher , Count duplicated

Count duplicated


Tag: neo4j,cypher

Imagine that i have a graph in which for every pair of nodes m,n of type Nod1 there can be a node k of type Nod2 that connect them through relationships of type Rel, that is, there can be multiple patterns of the kind p=(m:Nod1)-[r:Rel]-(k:Nod2)-[s:Rel]-(n:Nod1). For a given node m (satisfying for example m.key="whatever") how can i find the node n that maximizes the number of nodes k that connect m to n? For example: imagine that there are 3 nodes k that connects m to n1 satisfying n1.key="hello" and 10 nodes k that connects m to n2 satisfying n2.key="world"; how to build a query that retrieves the node n2? :)

The title of the question is count duplicated, because i think that the problem is solved if i can count all "duplicated" patterns for each node n (that is, all patterns that has n as "endnode")!! :)


Start by matching your m; then match the pattern you want, then filter by distinct n nodes, and count the number of k nodes connected via that n node, and you should be there.

MATCH (m:Nod1 { key: "whatever" })
MATCH (m)-[r:Rel]-(k:Nod2)-[s:Rel]-(n:Nod1)
RETURN distinct(n), count(k) as x


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