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bash getopts validate options

linux,bash,scripting,command-line-arguments,getopts
I have following code in bash script: # argument validation and usage help usage() { cat << EOF usage: $0 options File Integrity Monitoring Script: OPTIONS: -b input file for [backup] -r input file for [diff report] -l list backup files EOF } if [ $# -eq 0 ] then...

using getopts did not get the input value

bash,while-loop,getopts
I am running the below script, but it looks like the $filename or $srvname did not get the input value. say for eg: ./test.sh -n abcd.net gives the output echo 'Filename or node name must be defined.' it means that, the $srvname did not get the value "abcd.net", please advise...

Options not parse as Argument in Unix

bash,command-line-arguments,getopt,getopts
I has an existing script which works on $1 $2 $3, etc. I want to add an optional argument without disturbing the order. Do we have some ready made solution for: If a valid option (using getopts) is found, this index of argument should not be considered as argument....

how to use getopt/getopts

bash,shell,unix,getopts
So, I've learned how to pass in arguments in my bash script. The next step for me is to pass in a flag with the argument. For example,-id 12345, -d YES or -d NO, -h localhost. So, I'm looking to execute like so: ./Build.sh -id 12345 -d YES -h localhost...

Bash - optional argument required but not passed for use in getopts

bash,shell,getopts
How do I flag an error in a bash script which requires an argument for getopt, but the user didn't pass it? e.g. the script below requires an argument for option "t": #!/bin/bash while getopts "ht:" OPTION do case $OPTION in h) echo "Hi" ;; t) echo You entered $OPTARG...

Correct way of using getopts

shell,getopts
Executing following script gives error for mkdir command PATH=/root while getopts "r" name; do case $name in r) PATH=/home ;; *) echo "Usage: $0 -r" ;; esac done echo $PATH mkdir new error: ./test.sh: line 15: mkdir: command not found What's wrong in this script ?...

Checking for lack of flags in bash

bash,scripting,sh,getopts
If I were to do something like this to process arguments in bash, how would I check if there were no arguments? It doesn't seem to go to the *) case, but I'd still like to put a usage statement in there somewhere. while getopts 'ias' flag; do case "${flag}"...

Pass parameters as option in custom getopts script in bash

bash,getopt,getopts
I'd like to pass options as a parameter. E.g.: mycommand -a 1 -t '-q -w 111' The script cannot recognize a string in quotes. I.e it gets only part of the string. getopts works the same - it see only -q. For custom getopts I use similar script (example): while...

Bash + print default character after user prompt

linux,bash,shell,for-loop,getopts
-I made a bash function like this: find_stuff () { list=`find $SEARCHPATH -type f -user $USERID -mmin -$SOMETIME -not -path '*/\.*' -exec ls -1rt {} \+` if [ -n "$list" ]; then for i in $list; do echo "Found item: "$i""; printf 'Is this ok? y/n [y]:' read arg case...