python,list,dictionary,printing,format , Printing dictornary with list order


Printing dictornary with list order

Question:

Tag: python,list,dictionary,printing,format

I have the following code, it is an address book (a list of dictionaries) and a list. The idea is to print the items from the dictionary in the order of the list (since dicts mess up the order of everything). When I run this code, it throws an exception (as shown below). I am not sure what I'm doing wrong as I have tried many different variations and I keep coming back to this wondering why it's not working.

Please help?

addressBook = [
    {
    'Nickname': 'Jimmy',
    'Name': 'James Roberts',
    'Address': '2/50 Robe Street',
    'Phone': '0273503342'
    },
    {
    'Nickname': 'Bob',
    'Name': 'Robert',
    'Address': '1 Vivan Street',
    'Phone': '067578930'
    }
]

addressFields = ['Nickname', 'Name', 'Address', 'Phone']

def listAll(addressBook, addressFields):
    for i in addressBook:
        for key in addressFields:
            print("{0} {1}".format(key, addressBook[i][key]))

    print("{0} {1}".format(key, addressBook[i][key]))


TypeError: list indices must be integers, not dict

Answer:

First, you're missing a ' in the addressBook literal after 'James Roberts. Second, the issue was that you were doing addressBook[i][key] instead of i[key]. i already refers to a dictionary contained in addressBook, so your code was trying to use a list's element as an index to itself.

def listAll(addressBook, addressFields):
    for i in addressBook:
        for key in addressFields:
            print('{} {}'.format(key, i[key]))

Python 3-friendly one-liner:

def listAll(addressBook, addressFields):
    print(*('{} {}'.format(j, i[j]) for i in addressBook for j in addressFields), sep='\n')

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