I am using a dataframe that has multiple NA values so I was thinking about sorting the attributes based on their NA values. I was trying to use a `for`

loop and this is what I have so far:

```
> data <- read.csv("C:/Users/Nikita/Desktop/first1k.csv")
> for (i in 1:length(data) ) {
+ temp <- c(sum(is.na(data[i])))}
> temp
[1] 0
```

It is the first time I am using a for loop in r so I am sure it is just a silly syntax problem but I can't understand which one exactly.

Ultimately, I need a list that shows the name of the attribute and its NA count. This way I could sort the list and get the desired information. Here is some mock data to make it easier.

```
data <- data.frame(A = c(500, 600, 700, 1000),
B = c(500, 600, 700, NA),
C = c(NA, NA, 500, 700),
D = c(800, NA, 933, NA),
E = c(NA, NA, NA, NA))
```

Edit: Thank you all for the help. All three solution worked for me. I do wonder though if there is a one line code that will sort those attributes before I export them into a file. like I mentioned before, I am quite new in `r`

so I am not sure if it is possible.

Edit 2: When I run the sort is gives me the next error:

```
temp <- sort(temp)
Error in sort.int(x, na.last = na.last, decreasing = decreasing, ...) :
'x' must be atomic
```

Any idea why?

Answer:

The right way to do iterative code in R is to avoid explicit `for`

loops. Use `apply`

(and the company) instead. @jeremycg gave you the right R-ish answer. Regarding your code, you should make some editing to make it work.

```
temp <- c()
for (i in 1:length(data)){
temp[names(data)[i]] <- sum(is.na(data[i]))
}
```

You had `temp`

rewritten at each iteration. Moreover you didn't write the labels of your variables into `temp`

. Hence the output you see is the number of `NA`

s in the last column of your dataset.

**Regarding OP's edit**

```
temp <- sort(temp) # pass decreasing=T into arguments in case
# you want reversed order
```

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