Can any one tell me how to return a matched value to a comparison between a value and a column vector in MATLAB. So lets say the value to be compared is 200 and I got a column vector:

```
a = [21; 32; 433; 54; 42;]
```

I want to find which element in the vector `a`

returns the match for the comparison `200 <= a`

If I do: `x = any(200 <= a)`

the value of `x`

will be `0`

or `1`

based on if the condition satisfy. But if I want to know which value in vector `'a'`

satisfied the condition how can I find that out? In this case element 3 and value is 433

Answer:

The other answers are good, but `find`

is unnecessary. Whenever possible, use logical indexing instead. Seeing `200 <= a`

is a bit strange for me. I like seeing the variable on the left side, so this is the same as saying `a >= 200`

. In any case, you can do this:

```
vals = a(200 <= a);
```

`200 <= a`

would return a logical vector where `1`

denotes that the element satisfies the condition you're looking for and `0`

would mean that the condition isn't satisfied. If we displayed `200 <= a`

, this is what we get:

```
>> 200 <= a
ans =
0
0
1
0
0
```

This means that only the third element satisfies your criteria. If we used this logical vector and indexed into `a`

, we would return only those elements that satisfied your condition from `a`

. As such, we would get:

```
vals =
433
```

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