objective-c,swift,objective-c-blocks , Blocks in Swift shows error “Missing argument for parameter #2 in call” [closed]
Blocks in Swift shows error “Missing argument for parameter #2 in call” [closed]
Question:
Tag: objective-c,swift,objective-c-blocks
I'm now using Jonas Gessner's JGActionSheet with Swift in my project, and the sample was written by Objective-C, when I tried to convert the block to Swift, Xcode shows the error "Missing argument for parameter #2 in call", here is the code I written and the screenshot:
Objective-C Sample
JGActionSheet *sheet = [JGActionSheet actionSheetWithSections:sections];
[sheet setButtonPressedBlock:^(JGActionSheet *sheet, NSIndexPath *indexPath)
{
[sheet dismissAnimated:YES];
}];
Code I written in Swift
let actionSheet = JGActionSheet(sections: sections)
actionSheet.buttonPressedBlock {
(sheet: JGActionSheet!, indexPath: NSIndexPath!) in
actionSheet.dismissAnimated(true)
}
Error screenshot
Missing argument for parameter #2 in call
So please help me to figure this out and thanks very much!
Answer:
actionSheet.buttonPressedBlock is a property. You are trying to set it. So where's your equals sign? This is how you set things in Swift:
myThing.myProperty = myValue
The fact that you are trying to set this property to a block (a function) changes nothing. So:
let actionSheet = JGActionSheet(sections: sections)
actionSheet.buttonPressedBlock = {
(sheet: JGActionSheet!, indexPath: NSIndexPath!) in
actionSheet.dismissAnimated(true)
}
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