objective-c,swift,objective-c-blocks , Blocks in Swift shows error “Missing argument for parameter #2 in call” [closed]


Blocks in Swift shows error “Missing argument for parameter #2 in call” [closed]

Question:

Tag: objective-c,swift,objective-c-blocks

I'm now using Jonas Gessner's JGActionSheet with Swift in my project, and the sample was written by Objective-C, when I tried to convert the block to Swift, Xcode shows the error "Missing argument for parameter #2 in call", here is the code I written and the screenshot:

Objective-C Sample

JGActionSheet *sheet = [JGActionSheet actionSheetWithSections:sections];
[sheet setButtonPressedBlock:^(JGActionSheet *sheet, NSIndexPath *indexPath) 
{
    [sheet dismissAnimated:YES];
}];

Code I written in Swift

let actionSheet = JGActionSheet(sections: sections)
actionSheet.buttonPressedBlock {
    (sheet: JGActionSheet!, indexPath: NSIndexPath!) in
    actionSheet.dismissAnimated(true)
}

Error screenshot

Missing argument for parameter #2 in call

So please help me to figure this out and thanks very much!


Answer:

actionSheet.buttonPressedBlock is a property. You are trying to set it. So where's your equals sign? This is how you set things in Swift:

 myThing.myProperty = myValue

The fact that you are trying to set this property to a block (a function) changes nothing. So:

let actionSheet = JGActionSheet(sections: sections)
actionSheet.buttonPressedBlock = {
    (sheet: JGActionSheet!, indexPath: NSIndexPath!) in
    actionSheet.dismissAnimated(true)
}

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