javascript,ternary-operator , understanding Complex inArray ternary operator

## Question:

Tag: javascript,ternary-operator

I was just going through the inArray method code and came across the following ::

``````inArray: function (elem, arr, i) {
var len;

if (arr) {
if (indexOf) {
return indexOf.call(arr, elem, i);
}

len = arr.length;
i = i ? i < 0 ? Math.max(0, len + i) : i : 0;

for (; i < len; i++) {
// Skip accessing in sparse arrays
if (i in arr && arr[i] === elem) {
return i;
}
}
}

return -1;
},
``````

now i understand how tenary operators work , but can somebody tell me , how the below line of code really works ? is it even a ternary operator ?

``````i = i ? i < 0 ? Math.max( 0, len + i ) : i : 0;
``````

or is it some kind of a new construct in JS ?

Thank you.

Alex-z.

Original Statement:

``````i = i ? i < 0 ? Math.max(0, len + i) : i : 0;
``````

To understand it better,

``````i = i ? (i < 0 ? Math.max(0, len + i) : i) : 0;
//      ^                                ^
``````

Yes, this is nested `ternary operator` `? :`.

Following is the `if else` representation of the above statement, represented in `if..else` step by step.

``````if (i) {
i = i < 0 ? Math.max(0, len + i) : i;
} else {
i = 0;
}
``````

It works as follow:

``````if (i) {
if (i < 0) {
i = Math.max(0, len + i);
} else {
i = i;
}
} else {
i = 0;
}
``````

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